Sarthaks Test
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Solve the following equations and also check your result in each case:

\(\frac{5x}3-\frac{(x-1)}4\) = \(\frac{x-3}5\)

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 \(\frac{5x}3-\frac{(x-1)}4\) = \(\frac{x-3}5\)

On transposing \(\frac{x-3}5\) to LHS, we get

On taking LCM of 3 and 4; substituting x = \(-\frac{51}{73},\) we get

We got LHS=RHS

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