Sarthaks Test
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Solve the following equations and also check your result in each case:

\(\frac{(1-2x)}7-\frac{(x-1)}4=\frac{x-3}8\)

\(=\frac32+\frac {x}4\)

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 \(\frac{(1-2x)}7-\frac{(x-1)}4=\frac{x-3}8\)

\(=\frac32+\frac {x}4\)

On transposing \(\frac{x}4\) to LHS, we get

Taking RHS

We got LHS=RHS

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