Sum of two rational numbers = \(\frac{-1}{2}\)
One number = \(\frac{5}{6}\)
Let the other rational number = x
Now,
According to question,
\(\frac{5}{6}\)+ x = \(\frac{-1}{2}\)
\(\Rightarrow\) x = \(\frac{-1}{2}-\frac{5}{6}\)
\(\Rightarrow\) x \(=\frac{-3-5}{6}\)
\(\Rightarrow\) x = \(\frac{-8}{6}\)
In lowest terms,
x \(=\frac{-8÷2}{6÷2}= \frac{-4}{3}\)
Therefore, the other rational number is \(\frac{-4}{3}\)
