\(\frac{2-y}{y+7}=\frac{3}5\)
On cross multiplication, we get
5(2 - y) = 3(y + 7)
-5y + 10 = 3y + 21
On transposing 3y to LHS and to RHS
-5y - 3y = 21 - 10
-8y = 11
y = \(\frac{-11}8\)
Check:
Taking LHS
\(\frac{2-y}{y+7}\)
On substituting x = \(\frac{-11}8\) we get
We got LHS=RHS