\(\frac{2x+1}{3x-2}\) = \(\frac 59\)
On cross multiplication, we get
9(2x + 1) = 5(3x - 2)
18x + 9 = 15x - 10
On transposing 15x to LHS and 9 to RHS
18x - 15x = -9 -10
3x = -19
x = \(-\frac{19}3\)
Check:
Taking LHS
\(\frac{2x+1}{3x-2}\)
On substituting y = \(-\frac{19}3\) we get
We got LHS=RHS