Solve the following equations and verify your answer: (1 - 9y)/(19 - 3y) = 5/8

Question

Solve the following equations and verify your answer:

\(\frac{1-9y}{19-3y}=\frac 58\)

Answer 1

\(\frac{1-9y}{19-3y}=\frac58 \)

On cross multiplication, we get

8(1 - 9y) = 5(19 - 3y)-72y + 8 = 95 - 15y

On transposing - 15y to LHS and 8 to RHS

-72y + 15y = 95 - 8- 57y = 87

y = \(-\frac{29}{19}\)

Check:

Taking LHS

\(\frac{1-9y}{19-3y}\)

On substituting y = \(-\frac{29}{19}\) we get

We got LHS = RHS