Question

If a, b, c are distinct then the value of x satisfying \(\begin{vmatrix} 0 &x^2-a & x^3-b \\[0.3em] x^2+a & 0 & x^2+c \\[0.3em] x^4+b &x-c &0 \end{vmatrix}\) = 0 is

A. c 

B. a 

C. b 

D. 0

Answer 1

D. 0

Δ = \(\begin{vmatrix} 0 &x^2-a & x^3-b \\[0.3em] x^2+a & 0 & x^2+c \\[0.3em] x^4+b &x-c &0 \end{vmatrix}\)

Δ = 0

(this is possible when x = 0)