Question

Gunpowder contains 75% nitre and 10% sulphur. Find the amount of the gunpowder which carries 9 kg nitre. What amount of gunpowder would contain 2.3 kg sulphur?

Answer 1

Amount of nitre in gunpowder = 9 kg

Percentage of nitre in gunpowder = 75%

Let amount of gunpowder = x kg 

So,

\(=\frac{X\times75}{100}\) = 9

\(= {X} =\frac{9\times100}{75}\) = 12 kg

Amount of sulphur in gunpowder = 2.3 kg

 Percentage of sulphur in gunpowder = 10% 

Let amount of gunpoder = x kg 

So,

\(=\frac{X\times10}{100}\) = 2.3

\(={X} =\frac{2.3\times100}{10}\) = 23 kg