If a > 0 and discriminant of ax^2 + 2bx + c is negative, then Δ = |(a,b,ax+b)(b,c,bx+c)(ax+b,bx+c,0)| is ​

Question

If a > 0 and discriminant of ax² + 2bx + c is negative, then Δ = \(\begin{vmatrix} a& b & ax+b \\[0.3em] b & c & bx+c \\[0.3em] ax+b & bx+c&0 \end{vmatrix}\) is

A. positive 

B. (ac – b²)(ax² + 2bx + c) 

C. negative 

D. 0

Answer 1

Correct answer is D.

Discriminant of ax² + 2bx + c = 0

- (2ax + 2bx +c)(- b² + ac) < 0