Question

Ramesh bought two boxes for Rs 1300. He sold one box at a profit of 20% and the other box at a loss of 12%. If the selling price of both boxes is the same, find the cost price of each box.

Answer 1

Cost price of two boxes = Rs. 1300

Let cost price of one box = Rs. x

∴ Cost price of other box = Rs. 1300 – x

Selling price of first box = \(x +x\times \frac{20}{100}=x+\frac{x}{5}=Rs.\frac{6x}{5}\)

Selling price of second box = (1300 - x) -(1300 - x) x \(\frac{12}{100}\) = Rs. \(\frac{28600-22x}{25}\)

We have,

= \(\frac{6x}{5}\) = \(\frac{28600-22x}{25}\)

= 150x = 28600 x 5 - 110x

= x = \(\frac{28600-5}{260}\) = 550

Hence,

Cost price of first box = Rs. 550

Cost price of second box = 1300 – 550 = Rs. 750