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If the selling price of 18 oranges is equal to the cost price of 16 oranges, find the loss percent.

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Selling price of 18 oranges = cost price of 16 oranges

Let cost price of 1 orange = Rs. x

Selling price of 18 oranges = Rs. 16x

∴ selling price of 1 orange = \(\frac{16x}{18}\)

Loss = x - \(\frac{16x}{18}\) = Rs. \(\frac{2x}{18}\) = Rs. \(\frac{x}{9}\)

= Loss% = \(\frac{loss}{cost\,price}\)x 100 = \(\frac{\cfrac{x}{9}}{x}\)x 100 = \(\frac{1}{9}\)x 100 = \(11\frac{1}{9}\)%

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