Mark the correct alternative in the following :
Let A = \(\begin{bmatrix}
1 & sin\,\theta & 1 \\[0.3em]
-sin\,\theta & 1 &sin\,\theta \\[0.3em]
-1 &-sin\,\theta& 1
\end{bmatrix}\) , where 0 ≤ θ ≤ 2π. Then,
A. Det (A) = 0
B. Det (A) ∈ (2, ∞)
C. Det (A) ∈ (2, 4)
D. Det (A) ∈ [2, 4]