Question

Ravish sold his motorcycle to Vineet at a loss of 28%. Vineet spent Rs 1680 on its repairs and sold the motor cycle to Rahul for Rs 35910, thereby making a profit of 12.5%, find the cost price of the motor cycle for Ravish.

Answer 1

Let cost price of motorcycle for ravish = Rs. x

Loss% for ravish = 28%

Selling price for Ravish = \(x-x\times \frac{28}{100}\) = Rs. \(\frac{18x}{25}\)

Selling price for Ravish = cost price for vineet =  Rs. \(\frac{18x}{25}\)

Cost of repairing by vineet = Rs.1680

Total cost for vineet = \(\frac{18x}{25}\) + 1680 rs.

Selling price for vineet = Rs. 35910

Profit = 35910 - \(\frac{18x+42000}{25}\) = Rs. \(\frac{855750-18x}{25}\)

Profit percentage = 12.5% Given

Hence, by formula

= Gain% = \(\frac{gain}{cost\,price}\)x 100 = \(\frac{​​[\cfrac{855750-18x}{25}]}{[\cfrac{18x+42000}{25}]}\)x 100 = 12.5

= \(\frac{​​[\cfrac{855750-18x}{25}]}{[\cfrac{18x+42000}{25}]}\) = \(\frac{125}{1000}\) = \(\frac{1}{8}\)

= 162x = 6804000

= x = \(\frac{6804000}{162}\) = 42000

∴ cost price of motorcycle for Ravish = Rs.42000