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in Linear Equations by (34.9k points)
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Sunita is twice as old as Ashima. If six years is subtracted from Ashima’s age and four years added to Sunita’s age, then Sunita will be four times Ashim’s age. How old were they two years ago?

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Let the present age of Ashima is x years

Present age of Sunita is 2x years

Ashima’s new age = (x - 6) years

Sunita’s new age = (2x + 4) years

According to the question:

Therefore the age of Ashima is 14 years

Age of Sunita is 28 years

Two years agp, age of ashima = 14 - 2 = 12 yearsage of Sunita = 28 - 2 = 26 years

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