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in Continuity and Differentiability by (29.3k points)
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If \(\text{f(x)} = \begin{cases} 1, & x \leq -1\\ |x|, & -1< x < 1\\ 0, & x \geq 1 \end{cases}.\) Then, f is

A. Continuous at x = –1

B. Differentiable at x = –1

C. Everywhere continuous

D. Everywhere differentiable

1 Answer

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by (28.8k points)
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Best answer

Correct answer is A and B.

Checking the continuity at x = -1:

LHL at x = -1,

Hence, f(x) is continuous at x = -1.

Checking the differentiability at x = -1:

LHD at x = -1,

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