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Simplify:

(i) \(\frac{4}{9}\div\frac{-5}{12}\)

(ii) \(-8\div\frac{-7}{16}\)

(iii) \(\frac{-12}{7} \div(-18)\)

(iv) \(\frac{-1}{10}\div\frac{-8}{5}\)

(v) \(\frac{-16}{35}\div\frac{-15}{14}\)

(vi) \(\frac{-65}{14}\div\frac{13}{7}\)

(vii) \(\frac{-16}{35}\div\frac{-15}{14}\)

1 Answer

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Best answer

(i)

\(\frac{4}{9}\div\frac{-5}{12}\)

\(\frac{4}{9}\times\frac{12}{-5}\)

\(\frac{4\times12}{9\times-5}\)

\(\frac{48}{-45}=\frac{48\times-1}{-45\times-1}=\frac{-48}{45}\)

In lowest terms,

\(\frac{-48}{45} = \frac{-48\div3}{45\div3} = \frac{-16}{15}\)

(ii)

\(-8\div\frac{-7}{16}\)

\(\frac{-8}{1}\div\frac{-7}{16}\)

\(\frac{-8}{1}\times\frac{16}{-7}\)

\(\frac{-8\times16}{1\times-7}\)

\(\frac{-128}{-7}= \frac{-128\times-1}{-7\times-1}=\frac{128}{7}\)

(iii)

\(\frac{-12}{7}\div-18\)

\(\frac{-12}{7}\div\frac{-18}{1}\)

\(\frac{-12}{7}\times\frac{1}{-18}\)

\(\frac{-12\times1}{7\times-18}\)

\(\frac{-12\times1}{7\times-18}\)

\(\frac{-12}{-126}=\frac{-12\times-1}{-126\times-1}=\frac{12}{126}\)

In lowest terms,

\(\frac{12}{126}=\frac{12\div6}{126\div6}=\frac{2}{21}\)

(iv)

\(\frac{-1}{10}\div\frac{-8}{5}\)

\(\frac{-1}{10}\times\frac{5}{8}\)

\(\frac{-1\times5}{10\times-8}\)

\(\frac{-5}{-80}= \frac{-5\times-1}{-80\times-1}=\frac{5}{80}\)

In lowest terms,

\(\frac{5}{80}=\frac{5\div5}{80\div5}=\frac{1}{16}\)

(v)

\(\frac{-16}{35}\div\frac{-15}{14}\)

\(\frac{-16}{35}\times\frac{14}{-15}\)

\(\frac{-224}{-525}= \frac{-224\times-1}{-525\times-1}= \frac{224}{525}\)

In lowest terms,

\(\)\(\frac{224}{525}=\frac{224\div7}{525\div7} =\frac{32}{75}\)

(vi)

\(\frac{-65}{14}\div\frac{13}{7}\)

\(\frac{-65}{14}\times\frac{7}{13}\)

\(\frac{-65\times7}{14\times13}\)

\(\frac{-455}{182}= \frac{-455\times-1}{182\times-1}= \frac{-455}{182}\)

In lowest terms,

\(\frac{-455}{182}= \frac{-455\div7}{182\div7}= \frac{-65}{26}\)

Further,

\(\frac{-65}{182}= \frac{-65\div13}{26\div13}= \frac{-5}{2}\)

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