(a) By SSS congruence criterion, since it is given that AC = DF, AB = DE, BC = EF The three sides of one triangle are equal to the three corresponding sides of another triangle.
Therefore, ΔABC ≅ Δ DEF
(b) By SAS congruence criterion, since it is given that RP = ZX, RQ = ZY and ∠PRQ = ∠ XZY The two sides and one angle in one of the triangle are equal to the corresponding sides and the angle of other triangle. Therefore, Δ PQR ≅ Δ XYZ
(c) By ASA congruence criterion, since it is given that ∠MLN = ∠FGH, ∠NML = ∠HFG, ML = FG. The two angles and one side in one of the triangle are equal to the corresponding angles and side of other triangle. Therefore, Δ LMN ≅ Δ GFH
(d) By RHS congruence criterion, since it is given that EB = BD, AE = CB, ∠A = ∠C = 90°
Hypotenuse and one side of a right angled triangle are respectively equal to the hypotenuse and one side of another right angled triangle. Therefore, Δ ABE ≅ Δ CDB
