Sum of \(\frac{13}{5}\) and \(\frac{-12}{7}\)
\(\frac{13}{5}+\frac{-12}{7}\)
\(=\frac{13\times7+(-12)\times5}{35}\)
= \(\frac{91-60}{35}\)
= \(\frac{31}{35}\)
Product of \(\frac{-31}{7}\) and \(\frac{1}{-2}\)
\(\frac{-31}{7}\times\frac{1}{-2}\)
= \(\frac{-31\times1}{7\times-2}\)
= \(\frac{-31}{-14}\)
= \(\frac{31}{14}\)
Now,
According to the question,
\(\frac{31}{35}\div\frac{31}{14}\)
= \(\frac{31}{35}\times\frac{14}{31}\)
= \(\frac{2}{5}\)