Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
981 views
in Number System by (26.3k points)
closed by

Fill in the blanks:

(i) \(\frac{9}{8}\div(....) = \frac{-3}{2}\)

(ii) \((....) \div(\frac{-7}{5}) =\frac{10}{19}\)

(iii) \((....) \div(-3)=\frac{-4}{15}\)

(iv) \((-12)\div(....)= \frac{-6}{5}\)

1 Answer

+1 vote
by (25.0k points)
selected by
 
Best answer

(i)

\(\frac{9}{8}\div\text{x}(let)=\frac{-3}{2}\)

\(\Rightarrow\) \(\text{x} =\frac{9}{8}\div\frac{-3}{2}\)

\(\Rightarrow\) \(\text{x} =\frac{9}{8}\times\frac{2}{-3}\)

\(\Rightarrow\) \(\text{x}=\frac{9\times2}{8\times-3}\)

\(\Rightarrow\) \(\text{x}= \frac{18}{-24}= \frac{18\times-1}{-24\times-1}=\frac{-18}{24}\)

\(\Rightarrow\) \(\text{x}= \frac{-18}{24}= \frac{-18\div6}{24\div6}=\frac{-3}{4}\)

Therefore,

\(\frac{9}{8}\div\frac{-3}{4}= \frac{-3}{2}\)

(ii)

\(\text{x}(let)\div\frac{-7}{5}=\frac{10}{19}\)

\(\Rightarrow\) \(\text{x}=\frac{10}{19}\times\frac{-7}{5}\)

\(\Rightarrow\) \(\text{x} = \frac{10\times-7}{19\times5}\)

\(\Rightarrow\) \(\text{x} = \frac{-70}{95}=\frac{-70\div5}{95\div5}= \frac{-14}{19}\)

Therefore,

\(\frac{-14}{19}\div\frac{-7}{5}=\frac{10}{19}\)

(iii)

\(\text{x}(let) \div(-3)=\frac{-4}{15}\)

\(\Rightarrow\) \(\text{x}= \frac{-4}{15}\times(-3)\)

\(\Rightarrow\) \(\text{x}= \frac{-4\times-3}{15\times1}\)

\(\Rightarrow\) \(\text{x}= \frac{12}{15}=\frac{12\div3}{15\div3}=\frac{4}{5}\)

Therefore,

\(\frac{4}{5}\div(-3)=\frac{-4}{15}\)

(iv)

\(-12\div\text{x}(let)= \frac{-6}{5}\)

\(\Rightarrow \) \(\text{x}=-12\div\frac{-6}{5}\)

\(\Rightarrow \) \(\text{x}= -12\times\frac{5}{-6}\)

\(\Rightarrow \) \(\text{x}=\frac{-12\times5}{1\times-6}\)

\(\Rightarrow \) \(\text{x}= \frac{-60}{-6}=\frac{-60\times-1}{-6\times-1}=\frac{60}{6}\)

\(\Rightarrow \) \(\text{x} =\frac{60}{6}= \frac{60\div6}{6\div6}=10\)

Therefore,

\(-12\div10=\frac{-6}{5}\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...