We know in rhombus diagonals bisect each other at right angle.
In ΔAOB
AO = \(\frac{12}{2}\) = 6 cm , BO = \(\frac{16}{2}\) = 8 cm
Using pythagoras theorem in ΔAOB
AB2 = AO2 + BO2
AB2 = 62 + 82
AB2 = 36 + 64
AB2 = 100
AB = \(\sqrt{100}\) = 10 cm
Therefore each side of a rhombus is 10 cm.
