Length of park \(=36\frac{3}{5}\,m\)
Breadth of park \(=16\frac{2}{3}\,m\)
\(=36\frac{3}{5}\,m\times16\frac{2}{3}\,m\)
\(=\frac{183}{5}\,m\times\frac{50}{3}\,m\)
\(=\frac{183\times50}{5\times3}\,m\)
\(=\frac{9150}{15}\,m^2\)
\(=610\,m^2\)
Hence,
Area of park \(=610\,m^2\)