Given,
Rate of interest = 2% p.a
Time = 2 years
Amount = Rs.10404
Let principal = Rs. P
So,
A \(={P}[({1}+\frac{R}{100})^T]\)
\(={P}[({1}+\frac{2}{100})^2]\) = 10404
\(={P}\times\frac{51}{50}\times\frac{51}{50}\) = 10404
\(={P}=\frac{10404 \times 50 \times 50}{51\times51}\) = Rs. 10000
Hence,
Principal = Rs.10000