Given,
Compound interest = Rs.375
Principal = Rs.1800
Rate = 10% p.a
Let time = T years
So,
= compound interest \(={P}[({1}+\frac{R}{100})^T-1]\)
\(= 1800[({1}+\frac{10}{100})^T-1]\) = 378
\(= 1800\times(\frac{11}{10})^T\) = 378 +1800 = 2178
\(=(\frac{11}{10})^T\) \(=\frac{2178}{1800}\) \(=\frac{726}{600}\) \(=\frac{121}{100}\) \(=(\frac{11}{10})^2\)
= T = 2 years
Hence.
Time = 2 years
