Question

Three years ago, the population of a town was 50000. If the annual increase during three successive years be at the rate of 4%, 5% and 3% respectively, find the present population.

Answer 1

Given, 

Population of town 3 years ago was = 50000 

Annual increasing in 3 years = 4% ,5%, 3% respectively 

Let present population = X 

So

\(=50000({1}+\frac{4}{100})({1}+\frac{5}{100})({1}+\frac{3}{100})\) = x

\(= 50000\times\frac{26}{25}\times\frac{21}{20}\times\frac{103}{100}\) = x

= x = 56238

Hence, 

Present population of town = 56238