In Δ BAT and Δ BAC, given triangles are congruent so the corresponding parts are: B ↔ B, A ↔ A, T ↔ C
Thus, Δ BCA ≅ Δ BTA [By SSS congruence rule]
InΔ QRS and Δ TPQ, given triangles are congruent so the corresponding parts are: P ↔ R, T ↔ Q, Q ↔ S
Thus, Δ QRS ≅ Δ TPQ [By SSS congruence rule]
