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he population of a town increases at the rate of 40 per thousand annually. If the present population be 175760, what was the population three years ago.

1 Answer

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Best answer

Given, 

Increase rate of population of town = \(\frac{40}{1000}\times100\) = 4% annually

Present population of town = 175760 

Let population of town 3 years ago was = X 

So,

\(= x({1}+\frac{4}{100})({1}+\frac{4}{100})({1}+\frac{4}{100})\) = 175760

\(=x\times\frac{26}{25}\times\frac{26}{25}\times\frac{26}{25}\) = 175760

\(= x = \frac{(175760 \times 25 \times 25 \times 25)}{26\times 26 \times 26}\) = 156250

Hence, 

Population of town 3 years ago was = 156250

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