Given,
Present value of machine = Rs.100000
Rate of depreciation = 10% per annum
So,
Value of machine after 2 years \(= 100000({1}-\frac{10}{100})({1}-\frac{10}{100})\)
\(= 100000\times\frac{9}{10}\times\frac{9}{10}\) = Rs. 8100
Total depreciation during this period = Rs.(100000 – 8100) = Rs.19000