Given,
Depreciation rate of machine = 10% p.a
Present value of machine = Rs.43740
Let its purchase price 3 years ago = Rs. x
So,
\(=x({1}+\frac{10}{100})({1}+\frac{10}{100})({1}+\frac{10}{100})\) = 43740
\(x\times\frac{11}{10}\times\frac{11}{10}\times\frac{11}{10}\) = 43740
\(= x =\frac{43740 \times 10 \times 10 \times 10}{11 \times 11 \times 11}\) = 60000
Hence,
Purchase price of machine was = Rs.60000