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The value of a machine depreciates at the rate of 10% per annum. It was purchased 3 years ago. If its present value is Rs. 43740, find its purchase price

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Best answer

Given, 

Depreciation rate of machine = 10% p.a 

Present value of machine = Rs.43740 

Let its purchase price 3 years ago = Rs. x

So,

\(=x({1}+\frac{10}{100})({1}+\frac{10}{100})({1}+\frac{10}{100})\) = 43740

\(x\times\frac{11}{10}\times\frac{11}{10}\times\frac{11}{10}\) = 43740

\(= x =\frac{43740 \times 10 \times 10 \times 10}{11 \times 11 \times 11}\) = 60000

Hence, 

Purchase price of machine was = Rs.60000

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