Given,
Present value of refrigerator = Rs. 9680
Rate of depreciation = 12%
Let price of it 2 years ago = Rs.X
So,
\(=x({1}-\frac{12}{100})({1}-\frac{12}{100})\) = 9680
\(=x\times\frac{22}{25}\times\frac{22}{25}\) = 9680
\(= x =\frac{(9680 \times 25 \times 25)}{22\times22}\) = 12500
Hence,
Price of refrigerator 2 years ago was = Rs.12500