Let the number added be x
Then,
\(\frac{-2}{3}+\text{x}=\frac{3}{4}\)
\(\Rightarrow\) \(\text{x}=\frac{3}{4}-\frac{-2}{3}\)
\(\Rightarrow\) \(\text{x}=\frac{3\times3-(-2)\times4}{12}\)
\(\Rightarrow\) \(\text{x}=\frac{9+8}{12}\)
\(\Rightarrow\) \(\text{x}=\frac{17}{12}\)