Given,
Diameter of roller = 84 cm
Radius of roller = \(\frac{84}{2}\) = 42 cm
Length of roller = 120 cm
So,
Curved surface area of roller = 2πrh = 2 x \(\frac{22}{7}\) x 42 x 120 = 31680 cm2
No. of revolution it takes to level the ground = 500 given
Hence,
Area of play ground = 500 × 31680 = 15840000 cm2 = 1584 m2