Question

A cylindrical container with diameter of base 56 cm contains sufficient water to submerge a rectangular solid of iron with dimensions 32 cm × 22 cm × 14 cm. Find the rise in the level of the water when the solid is completely submerged.

Answer 1

Given,

Diameter of base of cylindrical vessel = 56 cm

Radius of base = \(\frac{56}{2}\) = 28 cm

Dimensions of rectangular solid vessel = 32 cm ×22 cm×14 cm

let rise in water level in vessel = h cm

so,

Volume of vessel = πr²h = \(\frac{22}{7}\) x 28 x 28 x h cm³

= \(\frac{22}{7}\) x 28 x 28 x h = 32 x 22 x 14

= h = \(\frac{32\times 22\times 14\times 7}{22\times 28\times 28}\) = 4 cm