Given,
Dimensions of rectangular sheet = 30 cm× 18 cm
Case (i)
when paper is rolled along its length:
= 2πr = 30
= r = \(\frac{30}{2π}\) cm
= height = 18 cm
Volume of cylinder thus formed = πr2h = π x (\(\frac{30}{2π}\))2 x 18 cm3
Case (ii)
When paper is rolled along its breadth:
= 2πr = 18
= r = \(\frac{18}{2π}\) cm
= Height = 30 cm
Volume of cylinder thus formed = πr2h = π(\(\frac{18}{2π}\))2 x 30
Hence,
= \(\frac{volume\,of\,cylinder\,1}{volume\,of\,cylinder\,2}\) = \(\cfrac{[π(\frac{30}{2π})^2\times 18]}{[π(\frac{18}{2π})^2\times 30]}\) = \(\frac{30}{18}\) = \(\frac{5}{3}\)