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The rain which falls on a roof 18 m long and 16.5 m wide is allowed to be stored in a cylindrical tank 8 m in diameter. If it rains 10 cm on a day, what is the rise of water level in the tank due to it?

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Given,

Dimensions of roof = 18 m × 16.5 m

Diameter of cylindrical tank = 8 m

Radius of tank = \(\frac{8}{2}\) = 4 m

it rains 10 cm a day

Let 'h' be the rise in level of tank

so,

= πr2h = l x b x h

\(\frac{22}{7}\)x 4 x 4 x h = 18 x 16.5 x 0.1

= h = \(\frac{18\times 16\times 5\times 0.1\times 7}{22\times 4\times 4}\) = 0.5906 m = 59.06 cm

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