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If y = loge (x), then find Δy when x = 3 and Δx = 0.03.

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If y = loge x, then find Δy when x = 3 and Δx = 0.03.

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Given that

Y = log x then y’ = 1/x

Δy = ?

X = 3

Δx = 0.03

By putting the values of above in the formula \(\frac{dy}{dx} = \frac{\Delta y}{\Delta x}\) we get

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