Given,
inner radius of tap = 0.75 cm
Rate of water flow through it = 7 m/s = 700 cm/s
so,
volume of water per second derived from tap = πr2l = \(\frac{22}{7}\)x 0.75 x 0.75 x 700 = 1237.5 cm3
Volume of water derived in 1 hour (3600 sec) = \(\frac{1237.5\times 3600}{1000}\) = 4455 litre