Given,
Width of roller = 63 cm
Girth (perimeter) = 440 cm
= 2πR = 440
= 2 x \(\frac{22}{7}\) x R = 440
= R = \(\frac{440\times 7}{44}\) = 70 cm
thickness of roller = 4 cm
inner radius = R - thickness = 70 - 4 = 66 cm
Volume of cylindrical iron = π(R2 - r2)l = \(\frac{22}{7}\) x (702 - 662)63 = \(\frac{22}{7}\)x 594 x 63 = 107712 cm3