Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
361 views
in Number System by (36.4k points)
closed by

Simplify the following expressions:

(i) (\(\sqrt{3}\) + \(\sqrt7\))2

(ii) (\(\sqrt5\) - \(\sqrt{3}\))2

(iii) (2\(\sqrt5\) + 3\(\sqrt2\))2

1 Answer

+1 vote
by (38.0k points)
selected by
 
Best answer

(i)  (\(\sqrt{3}\) + \(\sqrt7\))2 = (\(\sqrt{3}\))2 + 2 x \(\sqrt{3}\) x \(\sqrt7\) + (\(\sqrt7\))2

Because: (a + b)2 = (a)2 + 2 x \(\sqrt{a}\) x \(\sqrt{b}\) + (b)2

= 3 + 2\(\sqrt{3\times 7}\) + 7

= 10 + 2\(\sqrt21\)

(ii)  (\(\sqrt5\) - \(\sqrt{3}\))2 = (\(\sqrt5\))2 - 2 x \(\sqrt5\) x \(\sqrt3\) + (\(\sqrt3\))2

(a)2 - 2 x \(\sqrt{a}\) x \(\sqrt{b}\) + (b)2

= 5 - 2\(\sqrt{5\times 3}\) + 3

= 8 - 2\(\sqrt15\)

(iii)  (2\(\sqrt5\) + 3\(\sqrt2\))2 = (2\(\sqrt5\))2 + 2(2\(\sqrt5\)) x (3\(\sqrt2\)) + (3\(\sqrt2\))2

= 22\(\sqrt5\)2 + 2 x 2 x 3 x \(\sqrt{5\times 2}\) + 32 \(\sqrt2\)2

= 4 x 5 + 12\(\sqrt{5\times 2}\) + 9 x 2

= 20 + 12\(\sqrt10\) + 18

= 38 + 12\(\sqrt10\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...