If x = a cos nt – b sin nt and d^2y/dt^2= λx, then find the value of λ.

Question

If x = a cos nt – b sin nt and \(\frac{d^2y}{dt^2}=\lambda x,\) then find the value of λ.

Answer 1

Given:

y=a cos nt-b sin nt

λy= -n² (a cos nt-b sin nt )

λy= - n²y

λ= -n²