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If y = x + ex , find \(\frac{d^2x}{dy^2}.\)

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Best answer

Given:

\(y=x+e^x\)

\(\frac{d^2x}{d^2y}=\frac{1}{\frac{d^2y}{dx^2}}\)

\(\frac{dy}{dx}=1+e^x\)

\(\frac{d^2y}{dx^2}=e^x\)

\(\frac{d^2x}{d^2y}=\frac{1}{e^x}\)

=e-x

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