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If y = |x – x2|, then find \(\frac{d^2y}{dx^2}.\)

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Given:

y = |x - x2|

y = \(\begin{cases}x-x^2;&x\geq0\\x^2-x;&x\leq0\end{cases}\)

\(\frac{dy}{dx}=\begin{cases}1-2x;&x\geq0\\2x-1;&x\leq0\end{cases}\)

\(\frac{d^2y}{dx^2}=\begin{cases}-2;&x\geq0\\2;&x\leq0\end{cases}\)

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