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Steam at 100°C is passed into 1.1 kg of water contained in a calorimeter of water equivalent 0.02kg at 15°C till the temperature of the calorimeter and its contents rises at 80°C.The mass of the steam condensed in kilogram is

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Let x be the mass of steam condensed. The heat obtained calorimeter with water is equal the heat from condensing x kg of steam and the heat from cooling x kg of water to the final temperature of calorimeter with water.

x∙L + x∙c∙(T3 − T2 ) = (m + mc)∙c∙(T2 − T1 ),

where L = 540 cal/g – latent heat of steam, c = 1 cal/g∙degree – specific heat of water,

 

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