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Find the values of each of the following correct to three places of decimals, it being given that √2 = 1.414, √3 = 1.732, √5 =2.236, √6 = 2.4495 and √10 = 3.162.

(i) \(\frac{3-\sqrt5}{3+2\sqrt5}\)

(ii) \(\frac{1-\sqrt2}{3-2\sqrt2}\)

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(i) We have \(\frac{3-\sqrt5}{3+2\sqrt5}\) rationalising factor for denominator is 3 - 2√5

We have √5 = 2.236

= 0.012

= the value of \(\frac{3-\sqrt5}{3+2\sqrt5}\) = 0.102

(ii) \(\frac{1-\sqrt2}{3-2\sqrt2}\) by putting the value of √2 in the equation we get

= 14.068

= 14.070

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