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The value of \(\sqrt{3-2\sqrt2}\) is

A. \(\sqrt3\)\(\sqrt2\)

B. \(\sqrt3\)\(\sqrt2\)

C. \(\sqrt5\)\(\sqrt6\)

D. none of these

1 Answer

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Best answer

\(\sqrt{3-2\sqrt2}\)

(try to break the terms in form of (a+b)2 or (a – b )2)

√(√2)2+ 12 – 2 ×√2×1) = √(√2-1)2 = √2 – 1.

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