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A bag contains 3 red balls, 5 black balls and 4 white balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is :

(i) White? 

(ii) red? 

(iii) black? 

(iv) not red?

1 Answer

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Best answer

(i) White? 

Total numbers of red balls = 3 

Number of black balls = 5 

Number of white balls = 4 

Total number of balls = 3 + 5 + 4 = 12

Probability of getting a white ball is = \(\frac{Total\,number\,of\,white\,balls}{Total\,number\,of\,balls}\) = \(\frac{4}{12}= \frac{1}{3}\)

(ii) red? 

Total numbers of red balls = 3 

Number of black balls = 5 

Number of white balls = 4 

Total number of balls = 3 + 5 + 4 = 12

Probability of getting a red ball is = \(\frac{Total\,number\,of\,red\,balls}{Total\,number\,of\,balls}\) = \(\frac{3}{12}= \frac{1}{4}\)

(iii) black? 

Total numbers of red balls = 3 

Number of black balls = 5 

Number of white balls = 4 

Total number of balls = 3 + 5 + 4 = 12

Probability of getting a black ball is = \(\frac{Total\,number\,of\,black\,balls}{Total\,number\,of\,balls}\) = \(\frac{5}{12}\)

(iv) not red? 

Total numbers of red balls = 3 

Number of black balls = 5 

Number of white balls = 4 

Total number of Non red balls = 5 + 4 = 9

Probability of getting a non red ball is = \(\frac{Total\,number\,of\,non\,red\,balls}{Total\,number\,of\,balls}\) = \(\frac{9}{12}=\frac{3}{4}\)

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