\(\frac{\sqrt{48}+\sqrt{32}}{\sqrt{27}+\sqrt{18}}\)
= \(\frac{4\sqrt{3}+4\sqrt{2}}{3\sqrt{3}+3\sqrt{2}}\) = \(\frac{4\sqrt{3}+4\sqrt{2}}{3\sqrt{3}+3\sqrt{2}}\) × \(\frac{3\sqrt{3}-3\sqrt{2}}{3\sqrt{3}-3\sqrt{2}}\)
= \(\frac{36+12\sqrt{6}-12\sqrt{6}-24}{(27-18)}\) = \(\frac{12}{9}\) = \(\frac{4}{3}\)