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Evaluate each of the following using identities:

(i) \((2x-\frac{1}{x})^2\)

(ii) (2x+y) (2x - y)

(iii) (a2b - b2a)2

(iv) (a – 0.1) (a +0.1)

(v) (1.5x2 - 0.3y2)(1.5x2 - 0.3y2)

1 Answer

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Best answer

(i) We know, (a - b)2 = a2 + b2 -2ab

Here,

a = 2x and b = \(\frac{1}{x}\)

\((2x-\frac{1}{x})^2\) = \((2x)^2-(\frac{1}{x})^2 - 2\times x\times \frac{1}{x}\)

\((4x)^2-(\frac{1}{x})^2 - 2\)

(ii) We know, (a-b)2 = (a+b) (a - b)

(2x+y)(2x-y) = (2x)2– y2 = 4x2 – y2

(iii) We know, (a - b)2 = a2 + b2 - 2ab

Here,

(a2b - b2a)2 = (a2b)2 + (b2a)2 - 2 x a2b x b2a

= a4b2 + a2b4 - 2a3b3

(iv) We know, (a-b)2 = (a+b) (a - b)

(a – 0.1)(a +0.1) = (a)2– (0.1)2

= a2 – 0.01

(v) We know, (a - b)2 = a2 - b2

(1.5x2 - 0.3y2)(1.5x2 - 0.3y2) = (1.5x2)2 - (0.3y2)2

= 2.25x4 - 0.09y4

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