Total numbers of white shocks = 6 pairs
Total numbers of black shocks = 3 pairs
Total number pairs of shocks = 6 + 3 = 9
Probability of getting a white shock is = \(\frac{Total\,number\,of\,white\,shocks}{Total\,number\,of\,shocks}\) = \(\frac{6}{9}=\frac{2}{3}\)
Probability of getting a black shock is = \(\frac{Total\,number\,of\,black\,shocks}{Total\,number\,of\,shocks}\) = \(\frac{3}{9}=\frac{1}{3}\)
