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If x + \(\frac{1}{x}\) = 11, find the value of x2\(\frac{1}{x^2}\)

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Here, we will use (a+b)2 = a2 + b2 +2ab

(x + \(\frac{1}{x}\)) = (11)

(x + \(\frac{1}{x}\))2 = (11)2

(x)2 + (\(\frac{1}{x}\))2 + 2 x x \(\frac{1}{x}\) = 121

(x)2 + (\(\frac{1}{x^2}\)) = 121 - 2

(x)2 + (\(\frac{1}{x^2}\)) = 119

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