Given,
\(2\text{x}^{2}\,-\frac{5}{6}\text{x}\,+\frac{1}{12}\)
= \(2\text{x}^{2}\,-\frac{1}{3}\text{x}\,-\frac{1}{2}\text{x}\,+\frac{1}{12}\)
= \(\text{x}(2\text{x}\,-\frac{1}{3})\,-\frac{1}{4}(2\text{x}\,-\frac{1}{3})\)
= \((2\text{x}\,-\frac{1}{3})(\text{x}\,-\frac{1}{4})\)